Re: Determining row of pixels among a group that has the max number

Thanks for the info so far. Sorry about the confusion regarding the
actual number of pixels. It is  90 of 10x1. The raw data is coming
from temperature sensors. We are trying to figure out the hotspots in
a flow. I am trying to think of simpler ways to pinpoint the bank of
sensors which has the hot spot.
Therefore I was thinking of creative ways to analyze the data instead
of just looking at it as a list of temperature points.

Is it possible using some algorithm to determine probabilistically
which of the banks has the max number of sensors with a temperature
above a given threshold ? i.e I dont need to know deterministically
which of the sensor banks has the hotspot. If I can know that it is
bank "x" with a probability of "y" that would also be acceptable.

And this is definitely not a hw problem :):)

Thank you once again.

On Jul 15, 6:12 am, Martin Brown <|||newspam...@[EMAIL PROTECTED]
>
wrote:
> homer123123...@[EMAIL PROTECTED]
 wrote:
> > Hello,
>
> > I am a newbie to the area of image processing. I have  a 30pixel by
> > 30pixel greyscale image. It consists of 30 groups of 1x10 pixels. I
> > need to find out which of the these groups has the maximum number of
> > pixels above a given threshold. The brute force way would be to
> > determine the number of pixels that are above a given threshold in
> > each of the 1x10pixels. Then, repeat this procedure for all 30 groups.
> > Sort them and then determine the group.
>
> Seems like it is either 90 of 10x1 pixels or 30 of 30x1. And sounds a
> bit like a homework question. But even so a hint or two may not go
amiss.
>
>
>
> > Is there an easier way to do this using some kind of filter or some
> > algorithm. I need to do this in hardware and will have to estimate the
> > power efficiency of the two techniques.
>
> If it was being programmed you could keep track of block with the best
> threshold N found so far and if it ever reaches 10 return an immediate
> result. You can give up on any blocks where 10-N have failed the
> threshold test (you already have a better block).
>
>
>
> > Any help is much appreciated.
>
> Regards,
> Martin Brown
> ** Posted fromhttp://www.teranews.com**